1 — Cardinality, Cantor’s Theorem, Series, Measure Theory
Lecture 01 covers early measure-theoretic foundations: countable vs uncountable sets, Cantor’s diagonal argument (including $vert A\vert <\vert 2^A\vert $), binary expansions showing ($(0,1)$) is uncountable, basics of sequences/series (convergence, harmonic vs (p)-series, alternating divergence), and first steps in measure theory—definition of an algebra of sets and a measure on it.
1. Cardinality of Sets
A set is finite, countably infinite, or uncountable.
Definition (Cardinality)
For a set $A$, the cardinality $\vert A\vert $ is the “number of elements” in $A$.
- If there is a bijection $A \leftrightarrow \mathbb{N}$, then $A$ is countable.
- If no such bijection exists, $A$ is uncountable.
Examples of Countable Sets
- $\mathbb{N} = {1,2,3,\dots}$
- $\mathbb{Z} = {\dots,-2,-1,0,1,2,\dots}$
- $\mathbb{Q} = {\frac{m}{n}: m,n\in\mathbb{Z}, n\neq 0}$
A typical enumeration of $\mathbb{Q}$ uses the lattice of integer pairs $(m,n)$ arranged in diagonals.
Real numbers are uncountable
\(\vert \mathbb{R}\vert > \vert \mathbb{Z}\vert .\)
This is shown using Cantor’s diagonal argument.
2. Cantor’s Theorem: $\vert A\vert < \vert 2^A\vert $
Power Set
For any set $A$, the power set \(2^A = \{B : B\subseteq A\}\) has cardinality strictly greater than $A$.
Theorem (Cantor)
For every set $A$, \(\vert A\vert < \vert 2^A\vert .\)
Proof (Diagonal Argument)
Assume for contradiction that there is a bijection
\(f : A \to 2^A.\)
Define the set \(B = \{a\in A : a\notin f(a)\}.\)
Since $B\subseteq A$, if $f$ is onto, there must be some $b\in A$ such that \(f(b) = B.\)
Now consider whether $b\in B$:
- If $b\in B$, then by definition of $B$, $b\notin f(b)=B$. Contradiction.
- If $b\notin B$, then by definition of $B$, $b\in f(b)=B$. Contradiction.
Thus no bijection exists and $\vert A\vert < \vert 2^A\vert $.
3. Binary Expansions and the Uncountability of $(0,1)$
Every number in $(0,1)$ can be written as a binary expansion: \(x = \sum_{k=1}^\infty \frac{\varepsilon_k}{2^k}, \qquad \varepsilon_k \in \{0,1\}.\)
This identifies $(0,1)$ with a subset of ${0,1}^{\mathbb{N}}$.
Because ${0,1}^{\mathbb{N}}$ is uncountable, $(0,1)$ is uncountable.
4. Sequences and Series
Sequence
A sequence is a function \(a : \mathbb{N} \to \mathbb{R}, \qquad n\mapsto a_n.\)
Partial Sums and Series
The partial sums of a series are \(S_N = \sum_{i=1}^N a_i.\)
The series $\sum_{n=1}^\infty a_n$ converges if $\lim_{N\to\infty} S_N$ exists and is finite.
Basic Facts
- If $a_n \ge 0$ and $\sum a_n < \infty$, then $S_n$ is increasing and bounded, so it converges.
- Example:
- Harmonic series diverges: \(\sum_{n=1}^{\infty} \frac{1}{n} = \infty.\)
- $p$-series with $p>1$ converges: \(\sum_{n=1}^{\infty} \frac{1}{n^2} < \infty.\)
- Alternating series like $(-1)^n$ do not converge, because partial sums oscillate.
5. Measure Theory: First Definitions
Let $\Omega$ be a set.
Algebra of Sets
A collection $\mathcal{A}\subseteq 2^\Omega$ is an algebra if:
- $A,B \in \mathcal{A} \implies A\cap B \in \mathcal{A}$.
- $A\in \mathcal{A} \implies A^c \in \mathcal{A}$.
- $\varnothing \in \mathcal{A}$, hence $\Omega\in\mathcal{A}$.
- Closure under union follows from De Morgan: \(A\cup B = (A^c \cap B^c)^c.\)
Example
On $\Omega = \mathbb{R}$, let $\mathcal{A}$ be the set of finite unions of half-open intervals: \(\mathcal{A} = \bigcup_{k=1}^N (a_k,b_k], \quad \text{disjoint intervals}.\)
This is an algebra.
6. Measures
A measure on an algebra $\mathcal{A}$ is a function \(\mu : \mathcal{A} \to [0,\infty]\) such that:
- $\mu(A)\ge 0$ for all $A\in\mathcal{A}$.
- $\mu(\varnothing)=0$.
- Countable additivity for disjoint sets:
If $A_i \in \mathcal{A}$ are pairwise disjoint and $\bigcup_{i=1}^\infty A_i \in \mathcal{A}$, then \(\mu\!(\bigcup_{i=1}^\infty A_i) = \sum_{i=1}^\infty \mu(A_i).\)
This is the foundation for the probability measure $P$ later in the course.
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